35x^2-52x-8=0

Solution for 35x^2-52x-8=0 equation:

35x^2-52x-8=0

a = 35; b = -52; c = -8;
Δ = b2-4ac
Δ = -522-4·35·(-8)
Δ = 3824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3824}=\sqrt{16*239}=\sqrt{16}*\sqrt{239}=4\sqrt{239}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-4\sqrt{239}}{2*35}=\frac{52-4\sqrt{239}}{70}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+4\sqrt{239}}{2*35}=\frac{52+4\sqrt{239}}{70}
$